Given f(x)=2/3x-2, find a number c in the domain of f such that f(c)=0

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The domain of f is x, so we want a value of x that makes (2/3)x-2=0. Multiply through by 3: 2x-6=0, 2x=6, x=3. If f(c)=0 then c=3 because f(c)=f(3)=(2/3)3-2=0.

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