The Number of telephone calls that pass through a switchboard has poisson disteibution with mean equall to 2 per minute.The probability that no telephone calls pass through the switchboard is?
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P(k)=e^-m.m^k/k! where m=mean number of calls. So P(0)=e^-2*1=0.1353 or 13.53% within 1 minute.

At least, I think that's right.
by Top Rated User (1.2m points)

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