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asked Jul 27, 2017 in Other Math Topics by anonymous

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the diagram shows a circle,centre O.the lines AB,BC and CA touch the circle at P,Q and R respectively. explain CQO=90 degrees

The three lines AB,BC,CA are all tangent lines to the circle, and the circle is an inscriberd circle of the triangle ABC.

A tangent to a circle will touch it at one point only.

The tangent BC will touch the circle at the point Q.

O is the centre point of the circle.

OQ is a radius of the circle.

The radius of a circle to a point on the circle will always be perpindicular to the tangent at that point.

Hence, the radius OQ is perpindicular to the tangent BC.

i.e. the angle OQC is 90ยบ

answered Jul 27, 2017 by Fermat Level 11 User (79,760 points)

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