Factorize x^+8x+16-4y^

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I read this as x^2+8x+16-4y^2=(x+4)^2-4y^2=(x+4-2y)(x+4+2y).
by Top Rated User (1.2m points)

Factorize x^+8x+16-4y^

Assumiung that this is meant to be: x^2 + 8x + 16 - 4y^2, then it factorises as follows.

x^2 + 8x + 16 - 4y^2 =

(x + 4)^2 - (2y)^2 = 

{(x + 4) + 2y}{(x + 4) - 2y} =     (difference of two squares)

(x + 4 + 2y)(x + 4 - 2y)

 

by Level 11 User (81.5k points)

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