Find the area
in Geometry Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

I assume an equilateral triangle and its circumscribed circle. The centre of the triangle and circle are the same point and the radius is from the centre to a vertex. Joining two radii to vertices we get an isosceles triangle with angle at the centre=120 degrees (360/3) and the equal angles are 30 degrees. The isosceles triangle can be divided into two back-to-back right-angled triangles with hypotenuse (radius) = 4". The height of the right triangle is 4sin30=2 inches and the base = 4cos30 = 2√3 inches. The area of one such triangle = 2√3. There are 6 right triangles formed by the radii and vertices, so the area of the equilateral triangle is 6*2√3=12√3=20.78 sq in (approx).

by Top Rated User (642k points)

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
82,892 questions
87,496 answers
1,965 comments
3,942 users