Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject Hfor the given level of significance α.

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a/2=0.035 (96.5% confidence) for a 2-tailed test.

The critical z value for this is between 95% and 98% confidence levels, for which z=1.960 and 2.326.

|z| is less than both of these. This means that the z score is within bounds and the null-hypothesis fails to be rejected (in other words, the null-hypothesis appears to hold in a confidence level of 95%-98%, which includes 96.5%, assuming a normal distribution and a sufficiently large sample size).

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