aa66c+a7cc5=7b887 ,find a,b and C?

find a,b and C ?

asked Nov 13, 2016 in Algebra 1 Answers by anonymous

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aa66c

+a7cc5

7b887

5+c=7 so c=2:

aa662

+a7225

7b887

a+a=2a which is an even number but 7 is odd so there must be a carryover, therefore 2a+1=7, 2a=6, a=3.

If a=3, 3+7=10+b, so b=0.

Solution: a=3, b=0, c=2

answered Nov 13, 2016 by Rod Top Rated User (442,220 points)

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