find the dimensions of a rectangle whose perimeter is 80cm and its area is 375cm^2

Question

QUADRATIC EQUATIONS

Answer 1

If L and W are length and. width perimeter=80=2(L+W) and area=375=LW.

So, 2L+2W=80, L+W=40 and W=40-L. Substitute for W in the area equation: L(40-L)=375.

40L-L^2=375, L^2-40L+375=0=(L-15)(L-25) so L=15 or 25 and W=25 or 15 so the dimensions are 15 by 25.

Answer 2

Find the solution of Linear Equation: 3/x-5/y=9/5 5/x+4/y=-35/20