Alex, Gil and Meg shared 740 cards. Alex had 20 fewer cards than Gil and 1w0 fewer cards than Meg. How many cards did each one have?
in Word Problem Answers by Level 1 User (140 points)
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1 Answer

Lets think they have cards,  Alex = x , Gil = y and Meg = z. Then,
x+y+z = 740

Alex had 20 fewer cards than Gil. So,
x+20 = y

Alex had 120 fewer cards than Meg. So,
x+120 = z

 x+(x+20)+(x+120) = 740
3x + 140 = 740
x= 200

y= 220
z= 320

So Alex had 200 cards, Gil had 220 cards and Meg had 340 cards
by Level 2 User (1.7k points)

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