pls give the answer of this in integration
asked Jul 22, 2016 in Trigonometry Answers by nisarg

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Let X=sin(2x)sin(4x)sin(6x)=sin(2x)sin(4x)(sin(4x)cos(2x)+cos(4x)sin(2x))=




We want ∫Xdx.

Let p=sin(2x), dp=2cos(2x)dx.


That is: (3/4)sin^4(2x)-(2/3)sin^6(2x)+C where C=constant of integration.
answered Jul 22, 2016 by Rod Top Rated User (486,860 points)
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