Its from sample examination papers
asked Jul 9, 2016 in Trigonometry Answers by Srijan

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We know the expression sec^2A-tan^2A=1 using this equation. Given secA+tanA=4 . . (1) (secA+tanA)(secA-tanA)=1 (4)(secA-tanA)=1 (from eq.1) secA-tanA=1/4 . . .(2) Solving eq.1 & eq.2 We get SecA=9/8 & cosA=1/secA=8/9 SecA+cosA=9/8+8/9=145/72. That's it!
answered Jul 9, 2016 by Moin
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