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The wire represents the perimeter of the lot=2(length+width)=120, or length+width=60, so, if length=x, x+width=60 and width=60-x metres. The area is length times width=x(60-x)=60x-x^2. We can write f(x)=60x-x^2 where area=f(x) in square metres.

by Top Rated User (1.2m points)

Given,
Perimeter of the lot = 2(length+width) = 120

Length + width = 60

Let the length = L

so,
L + width = 60

Width = 60 -L

Area = length*width = L(60-L)

Area = 60L - L^2

Free Geometry Help

 

by Level 8 User (30.1k points)

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