pls help me in my homework thanks everyone
asked Jun 28, 2016 in Calculus Answers by Paul

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:

To avoid this verification in future, please log in or register.

3 Answers

There's a sort of cutoff point at x=-2 when f(x)=0. For x>-2 f(x) is increasing, and for x<-2 it's decreasing. At exactly x=-2 there's a saddle-point where the gradient is flat (horizontal) so x is nether increasing or decreasing.

answered Jun 29, 2016 by Rod Top Rated User (487,100 points)
let x and y from R:

(x + 2)^3 - (y + 2)^3 = (x-y)((x+2)^2 + (x+2)(y+2) + (y+2)^2)
((x+2)^2 + (x+2)(y+2) + (y+2)^2)>= ((x+2)^2 - 2 |(x+2)(y+2)| + (y+2)^2)>=0
(x + 2)^3 - (y + 2)^3 >= 0 => (x-y)>=0 => x >= y

than f is increasing in R


h(x) = x + 2 is increasing and g(x) = x^3 is increasing than f = goh(x) is increasing
answered Jun 29, 2016 by norrye
Function f(x) = (x+2)^3 is not increasing and decreasing
answered Jun 30, 2016 by John Marsh Level 8 User (30,400 points)
Welcome to, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
79,822 questions
83,639 answers
66,565 users