At last it is still in variable.
in Other Math Topics by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Subtract 19: x^4-2x^3+3x^2-ax+3a-26. Because we removed the remainder, x+1 must be a factor of the revised polynomial. We can use synthetic division to divide by x+1 using -1 as the root. When we do this we end up with 4a-20. This must be equal to zero for there to be no remainder, so 4a-20=0 and a=5.

-1 | 1 -2 3 -a  (3a-26)

......1 -1 3 -6  (a + 6)

......1 -3 6 (-a-6) | 0  4a-20=0, 4a=20, a=5.

Polynomial was x^4-2x^3+3x^2-5x+8.

 

by Top Rated User (1.2m points)

Related questions

2 answers
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
731,641 users