how do you reduce y3-3y2+y-3/y2-9

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1 Answer

(y3-3y2+y-3)/(y2-9)=

(y2(y-3)+(y-3))/((y-3)(y+3))=

(y2+1)/(y+3) because the common factor y-3 can be removed from denominator and numerator provided y≠3.

by Top Rated User (1.2m points)

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