Carlos who weights 104kg plans to lose 8kg during the first 3months of a diet,6kg during the next 3months,4.5kg during the following 3months and so on. this pattern of weight loss forms a geometric sequence. find the persons weight after a large number of years, assuming their diet is a successfu?
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Carlos who weights 104kg plans to lose 8kg during the first 3months of a diet,6kg during the next 3months,4.5kg during the following 3months and so on. this pattern of weight loss forms a geometric sequence. find the persons weight after a large number of years, assuming their diet is a successfu?

Weight = 104 kg.

a0 = 8 kg : weight loss in 1st quarter
a1 = 6 kg:       “         “    “  2nd     “
a2 = 4.5kg:     “        “    “   3rd     “
By observation, the common ratio, r = ¾

i.e. a_(n+1) = a_n * r,  or a_n = a_0*r^n

For a geometric sequence, the sum to infinity is
S = a0/(1 – r), where a0 = 8 and r = ¾

Then, S = 8 / (1 – ¾) = 8 / (1/4) = 32

Therefore total weight loss over a large number of years is 32 kg.

Weight after this time would be 104 – 32 = 72 kg

by Level 11 User (81.5k points)

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