How do you solve: 6x^3+10x^2+x+80 / 2x^2+1?

How do you solve; 6x^3+10x^2+x+80 / 2x^2+1?
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1 Answer

6x^3+10x^2+x+80 / 2x^2+1 = (3x + 5) +( - 2x + 75)/(2x^2 + 1)

 

                             3x + 5

    2x^2 + 1            6x^3+ 10x^2+x+80

                             6x^3            + 3x 

                           -                     -

                        -----------------------------------

                                       10x^2 - 2x  + 80 

                                       10x^2        + 5

                                     -                  -

                                -------------------------------

                                           - 2x + 75

by Level 8 User (36.8k points)

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