what is the answer to this problem? 1x-2=5+3x*x

Question

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Answer 1

x-2=3x^2+5

become 3x^2 -x+5+2=0

or 3x^2 -x+7=0

quadratik equashun giv roots:

x=0.1666666666666... +- 1.518405i (komplex variabels)

-b/2a=0.166666666...

b^2-4ac=-83, take square root av negativ number giv the i thang

Answer 2

Given 1x-2=5+3x*x
3x^2+5-x+2=0
3x^2-x+7=0
3x^2-x=7
-36/83(x-1/6)^2=1
x=1/6(1±i√83)