write an equation in-slope-intercept form with given slope and given point

Question

how do I write an equation in slope-intercept-form with the given slope of2/9  and the point of (5,2)

Answer 1

Start with point-slope form:

y - y1 = m(x - x1)

y - 2 = (2/9)(x - 5)

move stuff around to get it into slope-intercept form

y - 2 = (2/9)x - 10/9

y = (2/9)x - 10/9 + 2

y = (2/9)x - 10/9 + 18/9

y = (2/9)x + 8/9

that's slope-intercept form