The are of the pond itself is L(L-7) where L=length. The area with the walk adds 2' to length and width making the area (L+2)(L+2-7)=(L+2)(L-5). This is 58 sq ft bigger than the area of the pond: (L+2)(L-5)-L(L-7)=58.

L^2-3L-10-L^2+7L=58; 4L=68, so L=17' and width=10'.

CHECK: Pond area=170 sq ft. Pond area+walk=19*12=228 sq ft. 228-170=58 sq ft.

- All categories
- Pre-Algebra Answers 12,306
- Algebra 1 Answers 25,235
- Algebra 2 Answers 10,430
- Geometry Answers 5,157
- Trigonometry Answers 2,637
- Calculus Answers 5,997
- Statistics Answers 3,016
- Word Problem Answers 10,085
- Other Math Topics 6,622

81,485 questions

85,664 answers

2,174 comments

69,139 users