2x^2+4x+9=2(x^2+2x+9/2)=2(x^2+2x+1+7/2)=2((x+1)^2+7/2)=2(x+1)^2+7
3x+3=3(x+1)
The question has no equation to solve and the expression has limited factorisation.
If this is meant to be division, where is the division operator?
Let y=x+1, then the expressions becomes 3y(2y^2+1). (2y^2+1)/3y=(2/3)y+1/3y=(2/3)(x+1)+1/(3(x+1)).
If the questions was intended to be (3x+3)(2x^2+4x+9)=0, the solution is uniquely 3(x+1)=0, x+1=0, so x=-1.