which equation represents the line that passes through (2, -4) and is perpendicular to the graph of x-4y=8?

a. y= 1/4 x-2

b. y= 1/4x -9/2

c. y= 4x - 12

d. y= -4x + 4
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1 Answer

x-4y=8 can be written in standard form: y=x/4-2. The tangent has a slope of 1/4, so the normal (perpendicular) has a slope of -4 and would be represented by the equation y=-4x+b, where we find b by putting in the given point: -4=-8+b, so b=4 and y=-4x+4 (answer d).

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