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In triangle ABC;AB=7cm,AC=8cm,angle BAC=48° calculate a.the length BC b.find the size of angle BCA
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1 Answer

You use the cosine rule to find BC: BC^2=7^2+8^2-2*7*8cos48=113-112*0.6691=38.057cm. So BC=sqrt(38.057)=6.17cm approx.

Use the sine rule to find BCA: sinBCA/7=sin48/BC=0.12046, so sinBCA=7*0.12046=0.8432, making BCA=57.48° approx.

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