Can you please explain how to solve this?

N^3+4n^2+n+4=  Can you explain how to solve this?
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n^3+4n^2+n+4=n^2(n+4)+(n+4). So n+4 is a factor of both terms: (n^2+1)(n+4). If the expression equals 0, there's only one real solution, n+4=0, so n=-4. You can see this if we put n=-4 into the original expression: -64+64-4+4=0.

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