-5x+3y=3

4x+3y=30
in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

2 Answers

Find x and y intercepts for both equations by putting y=0 and finding x, then putting x=0 and finding y.

1st eqn: -5x=3, so x intercept=-3/5; 3y=3, so y intercept=1.

2nd eqn: 4x=30, so x intercept=15/2; 3y=30, so y intercept=10.

Draw a straight line to pass through the x and y intercepts for each line and where the lines cross is the solution of the two equations. The lines should cross at the point (3,6), so x=3, y=6 is the solution.

by Top Rated User (1.2m points)

Let 5x+3y=3......(1)
-5x+3y=3.......(2)

Add equation (1) and (2)
6y=6
y=1

Substitute y=1 in equation (1)
5x+3(1)=3
5x=0
x=0


Click here for the graph

Linear Equation Examples

by Level 8 User (30.1k points)

Related questions

1 answer
1 answer
1 answer
asked Mar 31, 2014 in Other Math Topics by anonymous | 617 views
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,334 answers
2,420 comments
761,092 users