Find the vertex make a table and graph the function
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

2 Answers

The function is a parabola in inverted U form.
The form of the equation tells us that the vertex is at t=4, h=12.8, because this point is uniquely the point where there is only one value of t, instead of two, for each value of h in range.
The vertex at (4,12.8) sits between the zeroes of the function given by putting h=0.
0.8(t-4)^2=12.8, so (t-4)^2=16 and t-4=±4. The zeroes are at (0,0) (the origin, where the h (vertical) and t (horizontal) axes intersect) and (8,0).
This information should be sufficient to sketch the graph.
We can tabulate some values:
t h
-2 -16
0 0
2 9.6
4 12.8
6 9.6
8 0
10 -16
by Top Rated User (813k points)

Given h=-0.8(t-4)^2+12.8
y = a(x – h)2 + k,
where (h, k) is the vertex.
Hence the vertex of the equation,
(4,12.8)



 

by Level 8 User (30.1k points)

Related questions

1 answer
asked Mar 16, 2013 in Calculus Answers by anonymous | 472 views
1 answer
asked Jul 17, 2014 in Other Math Topics by colin | 275 views
1 answer
1 answer
asked Oct 4, 2014 in Algebra 1 Answers by anonymous | 1.7k views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
85,985 questions
91,877 answers
2,227 comments
23,904 users