y=x^2+6x+9/x+3

Question

graph of rational function and find points of discontinuity.  I wasn't sure how to show "x squared" that's what the x^2 is supposed to be.  I'm clueless on this one

Answer 1

(x+3)²=x²+6x+9, so y=(x+3)²/(x+3)=x+3, except where x+3=0, that is, when x=-3, because that would create division by zero.

y=x+3 is a straight line passing through the intercepts at (-3,0) and (0,3).

There is one point of discontinuity, that is at the x-intercept (-3,0).