32-[4+6x-5(x+4)]= 4(3x+4)-[6(3x-4)+7-4x]

solve for the indicated variable
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1 Answer

32-[4+6x-5(x+4)]= 4(3x+4)-[6(3x-4)+7-4x]
32-[4+6x+(-5x-20)]=(12x+16)-[(18x-24)+7-4x]
32-[4+6x+-5x-20]=12x+16-[18x-24+7-4x]
32-[-16+x]=12x+16-[-17+14x]
32+16-x=12x+16+17-14x
48-x=33-2x
48=33-x
15=-x
-15=x
by Level 5 User (14.8k points)

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