This is a quadratic equation .. and i need to figure out theh values of the roots.. Rounding to the nearest hundredth
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1 Answer

 

    ax^2+bx+c  
2x^2-13x-8 x=(-b+sqrt(bb-4ac))/2a
    x=(-b-sqrt(bb-4ac))/2a
a b c x= 7
2 -13 -7 (13+sqrt(169+56))/4
      x= -0.5
      (13-sqrt(169+56))/4
by Level 5 User (14.8k points)

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