Algebra simultaneous equations
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 You can solve by substitution. From x-2y=3, x=3+2y. Substitute this in the other equation: 2(3+2y)+y=11. That is, 6+4y+y=11. So 6+5y=11. Subtract 6 from each side of the equation: 5y=5, so y=1. Therefore, x=3+2*1=5.

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