Please someone help
in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

2 Answers

This is not a linear function because the slope is varying. We know this because if we take two points and divide the difference between the y values by the difference between the x values we don't get the same value. Therefore there's no consistent slope. We could have a quadratic function of the form y=ax^2+bx+c. We find a, b and c, by substituting x and y values from the points we have and attempting to solve for a, b and c. When x=0, y=-2, so straight away we have c=-2. Our equation becomes y=ax^2+bx-2. Put x=1 and y=-1: -1=a+b-2, so a+b=1. Now we need another pair of values. Let's use x=y=2, so 2=4a+2b-2, and 4a+2b=4 or 2a+b=2. Substituting b=1-a we get 2a+1-a=2, so a=1 and therefore b=0. Our equation becomes y=x^2-2. Now we have to test if this fits the last point where x=3 and y=7. From the equation y=9-2=7. Bingo! It fits. So we have an equation that fits all the points: y=x^2-2.

by Top Rated User (1.2m points)

The function represented
y=x^2-2
(0, -2), (1, -1), (2, 2), (3, 7)

Algebra Functions

 

by Level 8 User (30.1k points)

Related questions

1 answer
1 answer
1 answer
1 answer
0 answers
1 answer
asked Oct 28, 2013 in Algebra 1 Answers by anonymous | 815 views
1 answer
asked Apr 14, 2022 by August | 488 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
733,514 users