Determine the truth value of the following statements. In each case justify your answer. a. Given that c,x,y are integers. If xy is not divisible by c then x is not divisible by c and yis also not divisible by c. b.If both ab and a+b are even the both a and b are even. {a,b are integers}
in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Let x=mc+n and y=pc+q, where 0<n,p<c and m, n, p and q are integers, then xy=mpc^2+c(mq+np)+nq. Dividing this product by c: mpc+mq+np+nq/c. By definition nq is not divisible by c. We can find values of m, n, p and q for all values of x and y, so, since nq is not divisible by c, neither are x and y. If ab and a+b are even then we can write: ab=2m and a+b=2n, where m and n are integers. a=2n-b can be substituted into the other equation giving b(2n-b)=2m. So 2nb-b^2=2m and b^2=2(nb-m). Therefore b^2 must be even, implying b must also be even and, since a=2n-2p=2(n-p) where 2p=b, a must be even. <\p>

by Top Rated User (1.2m points)

Related questions

1 answer
2 answers
asked Apr 5, 2012 in Algebra 1 Answers by anonymous | 1.1k views
0 answers
asked Mar 21, 2012 in Algebra 1 Answers by anonymous | 1.0k views
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
732,179 users