Find the gradient of the tangent to the curve

y= 3x^2+3x+1 at the point where x=2
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1 Answer

y = 3x^2 + 3x + 1
y' = 6x + 3

When x = 2, we have:

y' = 6(2) + 3
y' = 12 + 3
y' = 15

Hence, the gradient is 15 when x = 2.
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