How do you solve 4c+21=c squared

m∠EDF = m∠HDG. Use the Overlapping Angles Theorem to complete the following. m∠EDG = (c²)°, m∠FDG = (4c)°, m∠HDG = 21, c =
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4c  + 21 = c^2
c^2 - 4c - 21 = 0
(c - 7)(c + 3) = 0
c - 7 = 0 or c + 3 = 0
c = 7 or c = -3

I am not sure about the second part since I cannot see the figure involved.
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Thank you so much!!!
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