if logx-log(2x-1)=1,find x

If logx-log(2x-1)=1,find x
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2 Answers

log(x) -log(2x-1)=1

log[x/(2x-1)]=1

x/(2x-1)=base av log...maebee=10

x=10*(2x-1)

x=20x-10

19x=10

x=10/19...=0.3448275862069
by
log(x) -log(2x-1)=1 log [x/(2x - 1)] = 1 [x/(2x - 1)] = 10^1 [x/(2x - 1)] = 10 x = 10(2x - 1) x = 20x - 10 20x - x = 10 19x = 10 x = 10/19
by Level 1 User (180 points)

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