Suppose that the width of a certain rectangle is 5 inches more than one-fourth of its length. The perimeter of the rectangle is 50 inches. Find the length and width of the rectangle.
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1 Answer

Length = L

Width = W = 5 + L/4

Perimeter = P = 2L + 2W = 50

P = 2L + 2(5+L/4)

P = 2L + 10 + L/2

P = 4L/2 + 10 + L/2

P = 5L/2 + 10

P = (5/2)L + 10

(5/2)L + 10 = 50

(5/2)L = 40

L = 40 * (2/5)

L = 16

W = 5 + L/4

W = 5 + 16/4

W = 5 + 4

W = 9

Answer:  The length is 16 in and the width is 9 in.
by Level 13 User (103k points)

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