width of a rectangle is 5 in. is > 1/4 of its length perimeter of the rectangle is 50 in? find L&W

Suppose that the width of a certain rectangle is 5 inches more than one-fourth of its length. The perimeter of the rectangle is 50 inches. Find the length and width of the rectangle.
in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Length = L

Width = W = 5 + L/4

Perimeter = P = 2L + 2W = 50

P = 2L + 2(5+L/4)

P = 2L + 10 + L/2

P = 4L/2 + 10 + L/2

P = 5L/2 + 10

P = (5/2)L + 10

(5/2)L + 10 = 50

(5/2)L = 40

L = 40 * (2/5)

L = 16

W = 5 + L/4

W = 5 + 16/4

W = 5 + 4

W = 9

Answer:  The length is 16 in and the width is 9 in.
by Level 13 User (103k points)

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!

Most popular questions within the last 3000 days

  1. 50+50-25X0+2+2= (19)
  2. it takes 10 road workers 5 days to complete a road repair when working 2 hours a day.Working at the same pace,how many days will it take 2 people working 5 hours a day to finish it? (3)
  3. Solve 15 -1(12÷4+1)? (4)
  4. 8:4(5+2) (3)
  5. How can i represent 1/3; 3/3; 7/3; 10/3 and 15/3 on a number line? (1)

Most popular tags

87,516 questions
100,279 answers
2,420 comments
731,497 users