The perimeter of a certain rectangle is 16 times the width. The lenght is 12 cm more that the width. Find the length and width of the rectangle.
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2 Answers

Let the width be x.

The perimeter is 16x.

The length is x + 12.

The perimeter is twice the length added to twice the breadth, so we have:

16x = 2(x + 12) + 2x
16x = 2x + 24 + 2x
16x = 4x + 24
16x - 4x = 24
12x = 24
x = 24 / 12
x = 2 cm

x + 12 = 12 + 2 = 14 cm

Hence, the length is 14 cm and the width is 2 cm.
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Sole this problem y=x+4;(-7,1)
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