1/2x^3-x finding the zeros by factoring

in Trigonometry Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

1/2 x^3 - x

factor out an x

x (1/2 x^2 - 1)

set each equal to zero so x = 0 is one solution

1/2 x^2 - 1 = 0

add 1 to both sides

1/2 x^2 = 1

multiply both sides by 2

x^2 = 2

square root both sides keeping in mind that you need both positive and negative

x = sqroot (2) and x = -sqroot (2)

final answers x = 0, sqroot (2), -sqroot(2)
by Level 5 User (11.9k points)

Related questions

1 answer
asked May 12, 2013 in Trigonometry Answers by anonymous | 681 views
2 answers
1 answer
1 answer
asked Mar 15, 2013 in Algebra 2 Answers by anonymous | 804 views
1 answer
asked Dec 5, 2011 in Algebra 2 Answers by anonymous | 1.1k views
1 answer
asked Nov 14, 2011 in Algebra 2 Answers by anonymous | 1.2k views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,515 questions
100,352 answers
2,420 comments
766,161 users