x-10y=-30 3y-4x=46

Question

solve using substitude method

Answer 1

in first equation add 10y to both sides so x=(-30) + 10y

Then put this in for x into the 2nd equation so 3y-4(-30 + 10y) = 46

distribute on the left 3y + 120 - 40y = 46

combine like terms -37y + 120 = 46

subtract 120 from both sides -37y = (-74)

divide both sides by -37 and y=2

then put y=2 into x = (-30) + 10y

so x = (-30) + 10(2) which leaves x = (-10)

final answer (-10, 2)