a pilot entering a bay on course 60.3 degrees at the speed of 12 knots sees a light bearing 37.3 degrees true, and 20 mins later he sees it bearing 20 degrees true. if he keeps the same course and speed, (a) when will he be nearest to the lighthouse and how near; (b) when will he be 11 miles from the lighthouse?

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1 Answer

????????????????? yer "pilot" a boet in the water ?????????

speed av 12 nots, kant be a plane.

??????????? koers=60.3 deg ???? iz that 60.3 deg rite av NORTH ?????

???? sins wen kan sumwon in a boet bobbing around in the waves get a "beering tu 1/10 degree????

20 minuts=(1/3) our so boet go (12/3)=4 see-miles

???? "beering 37.3 deg true"... me assume yu meen direkshut tu sumthing on land=37.3 deg

rite av north

yu sae 20 minuts the "beering=20 deg true"...DONT MAKE NO SENS

Boet direkshun=60 deg, be rite av direkshun tu sumthun on land

So as boet go forward, direkshun tu that point get BIGGER

In theeree, boet will eventually get tu point weer RELATIV angel tu that thang=-90 deg

Thats the point av kloesest approech (assuming boet dont krash ashore B4 then)

But, 90 deg LEFT av 60 deg true=60-90=-30=330 deg.

The geometry dont make sens
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