solve 2x^2-12x+4=0 by completing the square. Express your result in simplest radical form, 
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subtract the 4 over. takke the 12 divide it in half and square it. add that number with no attached variables to both sides. solve into simplest radical form
by

Hi,

2x^2-12x+4=0

 by completing the square.

2 (x-3)^2-14 = 0

 

x = 3-sqrt(7)

x = 3+sqrt(7)

 

 

by
edited by
x^+6x+5=0
by
2x^2-12x+4=0

Divide through by 2: x^2-6x+2=0

Prepare to complete the square: x^2-6x=-2

Complete the square on the left-hand side: x^2-6x+9=-2+9=7 (add 9 to each side)

Square completed: (x-3)^2=7

Take square root of each side: (x-3)=±√7

x=3±√7, so x=5.646 or 0.354 approx.
by Top Rated User (680k points)

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