solve 1+0.03/4^1/52

algebra two dont understand very well need help.
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1 Answer

me assume that stuf shood be

1+{0.03 / [4^(1/52)]}

1/52=0.01923076923077

4^0.0192307....=1.02701805070877

0.03/1.0270180...=0.02921078162117

1+...=1.02921078162117
by

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