using substitution solve for 3x-4y=-2 -6x+8y=1

This is my last semester og algebra before i graduate and i dont understand linear equations using substitution and addition any one got some advice?
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1 Answer

First equation can be written: 3x=4y-2; so 6x=8y-4 and this value of 6x can be substituted into the second equation:

-(8y-4)+8y=1; -8y+4+8y=1; 4=1, which is false, so there are no solutions. 

Alternatively, multiply the first equation by -2: -6x+8y=4; but -6x+8y=1 from the second equation, therefore the equations are inconsistent and there can be no solutions.

by Top Rated User (1.2m points)

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