in Algebra 1 Answers by Level 1 User (140 points)

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Multiply the first equation by b^2 and the second by a^2 and we get: a^2b^2x+b^4y=b^2c^2 and a^2b^2x+a^4y=a^2d^2. We can eliminate the x term by subtracting one equation from the other: y(b^4-a^4)=b^2c^2-a^2d^2, from which y=(b^2c^2-a^2d^2)/(b^4-a^4) or (a^2d^2-b^2c^2)/(a^4-b^4). We could substitute this value of y into one of the original equations, but because of the symmetry of the equations we could simply repeat this process by multiplying the first equation by a^2 and the second by b^2 to eliminate the y term through subtraction. When we do this we get: x(a^4-b^4)=a^2c^2-b^2d^2, making x=(a^2c^2-b^2d^2)/(a^4-b^4) or (b^2d^2-a^2c^2)/(b^4-a^4).

by Top Rated User (761k points)

Related questions

1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
85,058 questions
90,184 answers
56,621 users