The perimeter of the inside edge of lane 1 is 325.66m. What would the perimeter of the inside edge of lane 2 be if lane 1 is 1m wide?

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1 Answer

??????????? maebee the "lane" be a serkel?????????

yu sae "inside edj leng=325.66 m"

If it be serkel, rim-leng=2*pi*rad=325.66, so rad=325.66/ (2pi)

inside radius=162.83/3.14159265358979323846264338327950288

=bout 51.83039883 m

Yer werd konfuzed, so me assume yu want leng av the OUTSIDE edj

outside radius=inside rad+1=52.83039883

outside leng=2*pi*52.83039883=331.9431853

differ=331.9431853 -325.66

=6.283185299...=2pi
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