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(8x)[(2x)]^-2=8
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1 Answer

Simplifying
8x = 2x2 + 8

Reorder the terms:
8x = 8 + 2x2

Solving
8x = 8 + 2x2

Solving for variable 'x'.

Reorder the terms:
-8 + 8x + -2x2 = 8 + 2x2 + -8 + -2x2

Reorder the terms:
-8 + 8x + -2x2 = 8 + -8 + 2x2 + -2x2

Combine like terms: 8 + -8 = 0
-8 + 8x + -2x2 = 0 + 2x2 + -2x2
-8 + 8x + -2x2 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-8 + 8x + -2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-4 + 4x + -1x2) = 0

Factor a trinomial.
2((-2 + x)(2 + -1x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-2 + x)' equal to zero and attempt to solve: Simplifying -2 + x = 0 Solving -2 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + x = 0 + 2 Combine like terms: -2 + 2 = 0 0 + x = 0 + 2 x = 0 + 2 Combine like terms: 0 + 2 = 2 x = 2 Simplifying x = 2

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {2, 2}

by Level 10 User (57.4k points)

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