f(x,y)=(3x+y^2)^(-1/2); find fx,fy,fxx,fxy

find partial derivatives, find fx, fy, fxx, fxy
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1 Answer

fᵪ=-(3/2)(3x+y²)^-(3/2), fᵧ=-y(3x+y²)^-(3/2),

fᵪᵪ=(27/4)(3x+y²)^-(5/2), fᵪᵧ=(9y/2)(3x+y²)^-(5/2).

by Top Rated User (1.2m points)

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