graphing with transformations

Question

find vertical and horizontal asymptotes.  State domain and range ; f(x)=  -1 / (x-7)^2

 

here's what I have   vertical asymptote = (x-7)^2 =0  x=7

                                horizontal asymptote = since power on denominator is higher

                                                                      than the numerator  y=0

I'm not sure about this, I have to graph, is (7,0) one point?  and I need at least two more points to graph.

Answer 1

ok, what you have so far is correct.

Vertical asymptote is x=7

horizontal asymptote y=0

now for the domain and range: the domain: The domain is all real numbers, x not equal to 7. This means the x values can be any number except for 7, they go to infinity on the left and right side of 7.

The range is: (negative infinity, 0 ) infinity is a sideways 8 , I don't know how to do it on this website.

Comments

thanks, al   these find the points really get to me.

Answer 2

o and to graph it some points are: im only picking perfect numbers that do not give a decimal y value because it is hard to graph those. and no (7,0) is not a point on the graph that is an asymptote it can never be a point.

(6,-1)

(8,-1)