Differentiate the following functions from first principles y³ + 3xy² - x³ = 3

Differentiate the following functions from first principles  y³ + 3xy² - x³ = 3
in Calculus Answers by Level 1 User (400 points)

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1 Answer

3y²dy/dx+3y²+6xydy/dx-3x²=0

y²dy/dx+y²+2xydy/dx-x²=0

(y²+2xy)dy/dx=x²-y²

dy/dx=(x²-y²)/(y²+2xy)=(x²-y²)/(y(y+2x))

by Top Rated User (1.2m points)

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