good Job the vertex is (-5,6)
the axis of symetry is x = -5
use:f(x) = (x + 5)^2 + 6
set x = 0 to get the y-intercept
y-intercept = (5)^2 + 6 = 25 + 6 = 31, (0, 31)
There are no x-intercepts because the parabola faces upward and does not cross the x-axis.
there are three points go graph and good luck! Happy New Year!
I labeled the x-axis by 2 and the y-axis by 5
there are two points (-5,6), (0,31) to graph these 2 points remember it is a bowl so round the line.
to get the reflective point of (0,31) go five to the left on the x-axis and 31 up or (-10,31). Same here round the line for the bowl.
now plug in values to continue:
f(1) = (1 + 5)^2 + 6 = 36 + 6 = 42
f(2) = (2 + 5)^2 + 6 = 49 + 6 = 54
this gives you a good right side of the parabola
f(-11) = 42 reflective of f(1)
f(-12) = 54 reflective of f(2).
hope this helps and notice the changes.